Biased Parallel Clippers Neso Academy - full contact karate

Thứ Hai, 18 tháng 2, 2019

Biased Parallel Clippers Neso Academy

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  1. Meghjit Mazumder: In reverse bias,two voltage sources,i.e.,Vi as well as 4V-both make the diode to operate in reverse bias,as a result,there is no conflict between 2 voltage sources,so there is no need to consider the effect of 4 volts separately.
  2. SnakeBuster: +Neso Academy You must be shameless to respond to this unimportant message while there are many much more important ones pointing out your errors waiting to be answered!
  3. prachi sikha: in reverse biasing why you had not considered the effect of 4 volts????
  4. Ayushi Shuman: in reverse bias, whole of the input voltage appears across output. isn't there some voltage drop across the 2.2kohm resistor?
  5. Robert Faney: When the diode is ON , it is a short circuit. So how can we just take the Battery alone when there is input Vs connected as well to consider. You acre correct if you did not have the V input and only had the battery. Think again !! Again we need to apply KVL to figure out the V output. It is not just a battery standing alone.
  6. Neso Academy: Welcome!
  7. Joydeep Debnath: Luis Mais Thanks got it!
  8. Other Guy: Hey Thankyou💚💜💛
  9. Bhavya Nandwani: in previous unbiased parallel clipper lecture sir u have applied kvl and get Vo=- Vi in negative half cycle
  10. ambarish dashora: But what will be the -ve pick value of output 🤔🤔
  11. Bellamkonda Manojsai: Doubts got clarified in a single video.thank u sir
  12. Kaushal Bhatt: Sir can you please explain how Vo is equal to Vi in the reverse biased condition of the diode
  13. Neso Academy: You can increase the speed up to two times in YouTube.
  14. anupam kumar: tu kis college me h???
  15. Gurpreet Kaur: i think u miss load resistance
  16. Sudip Roy: in 1:57 min F.B. V(i) > 4v u neglect the resistance voltage drop
  17. Hardev Talatiya: bhai kis nalle college mei hai. Input voltage is parallel to the diode. dekh dhyan se
  18. karthik krik: NO ,in the above ckt,though we the increase the biased 4v DC supply to a value greater than input peak value,the diode doesnt get on.and hence output appears same as input.
  19. Nischal Shrestha: How is it a parallel clippers example,sir?
  20. Luis Mais: Yeah. I'm wrong here.
  21. Gaurav Jaiswal: thanks sir
  22. Neso Academy: Welcome!
  23. shaurya godofwar: sir, how is this circuit "parallel " ? . Sir i do agree with you that it is baised as an external source is there and clipper as it clipped + cycle but how is it "parallel " ?
  24. Moazan Amjad: what if R input is not negligible and there is voltage drop in it?
  25. Ravi Teja: at 1:13,actually the 4v is forward biasing the circuit right as its flows from '+'to' -' tve
  26. karthik krik: No
  27. anupam kumar: agree with u. according to "introduction to clampers" videos Parallel clippers are those where load resistance is parallel with diode,.
  28. Ken Yan: i have the same confusion plz tell me which lecture the point was mentioned.
  29. Harshit Sachdev: Sir thank you for giving all such videos for free of cost.
  30. Zeaven Master: it becomes 4v because Vo is applied across 4v battery terminals :)
  31. Bipin Oli: your analysis is true for very high load resistance parallel to diode isn't it, else all the voltage drops across 2.2 k ohm resistor, so the voltage at top terminal of output is -Vi for positive half cycle and +Vi for negative cycle, therefore on negative half cycle Vo is zero until the Vi reaches 4v (because until then the potential at top terminal of output hasn't reach 4v to forward bias the diode). Therefore negative half cycle in output can have maximum of -4v not -8v.
  32. yasmina fetmouche: why in the negative half vo=vi how you applied kvl
  33. Sakib Akash: 4:40 output voltage equal to -Vi
  34. Luis Mais: he used an ideal diode there. which is equivalent to a close circuit.
  35. Intecer Ahmed: Thanks. Understood perfectly
  36. huzefa gul education: can we get Vo>Vi in clipper circuit???
  37. Neso Academy: There are two voltage source in the circuit, input ac supply (Vi) and 4V dc supply. In the positive half cycle, Vi is forward biasing the diode and 4V dc supply is reverse biasing the diode. So the stronger voltage source will decide the state of the diode. As input signal is alternating, for some time it is smaller than 4V dc supply and for remaining time it is greater than 4V supply. @2:15, diode is reverse bias and it is only possible when 4V dc supply is greater than the input supply (Considering positive half cycle). Now tell me where I have not considered the effect of 4V dc source.
  38. Sameer Bhavsar: The videos are good but tentatively a bit slow
  39. Zeaven Master: this means Vo = -Vi :) simple
  40. Joydeep Debnath: May I know the voltage during the (-)ve half cycle? I found it being mentioned in the comments as -8V, I think it should be -12V (8V+4V). Please clarify me.
  41. Pavan Siva Sai Kumar: why the voltage across resistor is zero for reverse bias of diode??
  42. Priyabrata Pradhan: Thanks for this elaboration. Will you please explain how Vr (2.2k) is zero in case of reverse biased.The parallel blocked elements (where diode is present) will be open circuit. However it forms a closed loop from Vin to Vout through the resistance 2.2k. How there will not be any voltage drop across the 2.2k resistance ? Confused a bit, please explain...
  43. Ankit singh: Diode not pass current only in those wire inwhich he connect See carefully v input is directly connected to v output when diode is reverse biased
  44. Luis Mais: depends to the biasing source if its positive or negative.
  45. Luis Mais: Sudip Roy because in clippers you are assuming that theres no current thats why there will be no voltage drop across in the resistor
  46. Dao Nguyen: love you <3
  47. Neso Academy: Your statement is not clear. Please explain what do you mean by '+' and '-'.
  48. Agniva Sharma: Could not understand anything........!!
  49. Mayank Ukani: Across all academies i have ever crossed yours is the best until now in every aspect and subject!
  50. sayantan panda: Thank u so much sir
  51. Luis Mais: its because the diode is in reverse bias.
  52. vips wins: What happens if a resistance is added next to positive side of diode?
  53. Eldho John Menachery: Sir,there is a mistake...once the diode becomes forward baised... The Vo is 4+diode knee voltage If it was silicon then Vo becomes 4.7
  54. Gaurang Pratap Singh: sir when diode is reverse biased it acts as open circuit so how Vo becomes equal to Vi shouldn't it be 0 pls correct me if i am wrong
  55. Johnson Chung: U saved me! Thank u <3
  56. Agniva Sharma: when the Vi is less then 4v then diode is in RB implies that no current flows through diode.Then how still are we getting a drop of 4v in output?
  57. mani sharan: sir if the diode voltage is less than the dc voltage we have to change the diode direction , sir please elobrate
  58. vaibhav purohit: sir parallel clipper load resistance parallel to diode .this is not a parallel clipper
  59. huzefa gul education: all confusions are vanished after watching this . thanks Neso Academy
  60. usman saleem: +Robert Faney Vin will be dropped across R
  61. Neso Academy: There is no mistake while calculating the output voltage, I've clearly mentioned that we are assuming the diode to be ideal and for ideal diodes forward voltage drop is 0V. Please watch previous lectures related diode.
  62. Kannan Iragavarapu: sir where is the load resistance which is parllel with the diode making it a parllel clipper
  63. muhammad ali: When vin =0 then Vo=-4v in +ve cycle then why u start waveform from 0 can u elaborate..i m confused
  64. Iccy Isak: How is this a parallel clipper? Pls ANSWER!
  65. karthik krik: As the diode doesn't conduct in R.B, diode becomes open,so we get the output voltage same as the input voltage,i.e input voltage doesnt pass through diode, directly goes to Vo.
  66. Bipin Oli: I tried simulating this circuit in proteus and found that I am wrong and your analysis is correct. Yeah indeed, the proper way to anlayze the circuit is by analyzing the voltages in two terminals of diode. I think i got it.
  67. Neso Academy: No! Please watch earlier lectures
  68. prachi sikha: 2:15
  69. MantisRay861: great video! I like how you broke it down
  70. Aditya Vikram Singh: why in reverse bias current from resistor is zero??
  71. Mariam Reporting live: Ya R8. I am also confuse.
  72. Neso Academy: Please mention the time.
  73. SnakeBuster: +Luis Mais diode is nowhere near the resistor... you are mistaking the voltage source with resistor, and even then your argument is stupidly wrong.
  74. Sutiksh V: sir how vo=vi in first cycle in reverse bias, i didn't get it?
  75. Khaled Syfullah Fuad: Can you please tell me why there is no current flowing through the resistor 2.2 Kohm when the diode is reversed biased?
  76. Karthik Karthiz: Sir,. at 1.39 during forward biased in + ve half cycle when vi > 4 v...vo should be 0...how it becomes 4 v??
  77. Shunya: How did you select 2.2 k ohms as resistance value ?? I have a question for you . In the laboratory experiment ,how do they choose the value of resistance (because they chose 10kilo ohms ) (Diode used is IN4007 with clipping being done for 2 volts both positive and negative) . Thanks in advance .
  78. Emarantia Ngomane: How is it parallel with no load resistance? it looks like a series circuit though
  79. Bhavya Nandwani: In unbiased parallel clipper at 3:24 sec
  80. Kaushal Bhatt: Shouldn't it be Vo = -Vi in the -ve half cycle? (4:50)
  81. Ankur Bharti: Thanks a lot...sir
  82. Bhavya Nandwani: negative half cycle Vo = -Vi isn't ?
  83. Safi Tariq: In negative cycle Vo = -8v.
  84. Neera Rajput: You are a life saver,, very well explained, thank you! Good job🙏
  85. Luis Mais: the current draws from negative(-) to positive (+)
  86. raj kumar: where is the load resistance?

Biased Parallel Clippers

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